Difference between revisions of User:Divenal/sandbox
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# <math>1 \text{ radian} = \frac{180}{\pi} \text{ degrees} = \frac{60 \times 180}{\pi} \text{ arc-minutes} </math> | # <math>1 \text{ radian} = \frac{180}{\pi} \text{ degrees} = \frac{60 \times 180}{\pi} \text{ arc-minutes} </math> | ||
Acuity is a measure of the ability to resolve small details, defined by the "minimum angle of resolution". Normal vision ("20/20", or 1.0) is the ability to resolve features subtending 1 minute of arc. | Acuity is a measure of the ability to resolve small details, defined by the "minimum angle of resolution". Normal vision ("20/20", or 1.0) is the ability to resolve features subtending 1 minute of arc. In order to have a bigger-is-better score, the reciprocal of the angle is usually used: | ||
In order to have a bigger-is-better score, the reciprocal of the angle is usually used: | |||
<math> \text{Acuity} = 1/A = \frac{pi}{60 \times 180} \times \frac{b}{a} = 0.00029 \times \frac{b}{a}</math> | <math> \text{Acuity} = 1/A = \frac{pi}{60 \times 180} \times \frac{b}{a} = 0.00029 \times \frac{b}{a}</math> | ||
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* -0.3 is "20/10" (2.0 or 0.5 arc-minutes) | * -0.3 is "20/10" (2.0 or 0.5 arc-minutes) | ||
On a Snellen chart | On a [[Snellen chart]] the letters are defined on a 5x5 grid: the detail to be resolved to distinguish between characters is one pixel of that grid. | ||
Here 'b' is the distance to the chart (eg 6m) and 'a' is the height of the letters. It's not critical that the eye is at the bottom or top of a row of letters - as long as the angles remain small, the numerical error is insignificant. | |||
Acuity is reported in the form "distance/letter-row", such as "20/40", etc. | |||
<math> \text{Acuity} = 5 \times 0.00029 \times \frac{ \text{distance to chart}}{\text{letter height}} | |||
= \frac{ \text{distance to chart}}{690 \times \text{letter height}}</math> | |||
Then, for example | |||
* for the "6/12" line, we need <math>690 \times \text{height} = 12m \implies \text{height} = 12m / 690 = 1.73cm</math> | |||
* for the "20/15" line, we need <math>690 \times \text{height} = 15ft \implies \text{height} = 15 * 12 / 690 = 0.26 \text{inch}</math> | |||
The denominator can be interpreted as the distance at which the letters subtend 5 minutes of arc. | |||