Difference between revisions of Presbyopia

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Presbyopia is the hardening of the [[lens]] in the [[eyeballs]] such that it becomes difficult to see [[near work]].  This is common in older adults and is commonly treated with [[reading glasses]] or [[bifocals]].
Presbyopia is the hardening of the [[lens]] in the [[eyeballs]] such that it becomes difficult to see [[near work]].  This is common in older adults and is commonly treated with [[reading glasses]] or [[bifocals]].


== Measuring ==
To determine your '''power of accommodation''', you need to measure your '''far power''' and '''near power'''.
Your '''far power''' is straightforward, and it’s the [[cm measurement]]s you normally do: just measure the furthest distance you can see clearly without blur, with a lens to adjust as needed. The far power is ''1/(distance to blur) - (lens power)''.
* For example, 80 cm with a -0.25 lens is calculated as 1/(80 cm) - (-0.25 D) = 1.25 D + 0.25 D = 1.5 D.
* It might be useful to use a plus lens to measure low myopia. For example, 80 cm with a +0.75 lens is calculated as 1/(80 cm) - (+0.75 D) = 0.5 D.
Your '''near power''' is the same, but you measure the '''closest''' distance you can see clearly without blur.
* For example, if the closest you can see is 10 cm without lenses, it’s calculated as 1/(10 cm) - 0 = 10 D.
* It might be useful to use a big minus lens to measure young people (don’t look through it for too long!). In the example above, you expect to see as close as 50 cm with a -8 lens, which is 1/(50 cm) - (-8 D) = 2 D + 8 D = 10 D.
The '''power of accommodation''' is (near power) - (far power). With the first example in each of the above, it would be 10 D - 1.5 D = 8.5 D.
===Caveats===
I’m not entirely sure how cylinder affects this measurement, so you’ll have to refine the technique if you have cylinder.
The cornea and lens actually have more power because the total power has to focus the image on your retina, but they cancel out in the subtraction step, so it’s easier to ignore them.
== Videos ==


{{#ev:vimeo|284921410||inline}}<br/>
{{#ev:vimeo|284921410||inline}}<br/>
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{{#ev:youtube|QvmOkVjwPyI||inline}}
{{#ev:youtube|QvmOkVjwPyI||inline}}


===Other Resources===
== Resources ==
 
* Here is a resource that may be of interest to people with presbyopia that was found in the Discord chat. The resource is used for training convergence. http://www.i-see.org/rizzi_charts_readvertical.pdf


Here is a resource that may be of interest to people with presbyopia that was found in the Discord chat. The resource is used for training convergence. http://www.i-see.org/rizzi_charts_readvertical.pdf
[[Category:Articles]]
[[Category:Articles]]
[[Category:Eye conditions]]
[[Category:Eye conditions]]

Revision as of 03:01, 5 February 2022

Presbyopia is the hardening of the lens in the eyeballs such that it becomes difficult to see near work. This is common in older adults and is commonly treated with reading glasses or bifocals.

Measuring

To determine your power of accommodation, you need to measure your far power and near power.

Your far power is straightforward, and it’s the cm measurements you normally do: just measure the furthest distance you can see clearly without blur, with a lens to adjust as needed. The far power is 1/(distance to blur) - (lens power).

  • For example, 80 cm with a -0.25 lens is calculated as 1/(80 cm) - (-0.25 D) = 1.25 D + 0.25 D = 1.5 D.
  • It might be useful to use a plus lens to measure low myopia. For example, 80 cm with a +0.75 lens is calculated as 1/(80 cm) - (+0.75 D) = 0.5 D.

Your near power is the same, but you measure the closest distance you can see clearly without blur.

  • For example, if the closest you can see is 10 cm without lenses, it’s calculated as 1/(10 cm) - 0 = 10 D.
  • It might be useful to use a big minus lens to measure young people (don’t look through it for too long!). In the example above, you expect to see as close as 50 cm with a -8 lens, which is 1/(50 cm) - (-8 D) = 2 D + 8 D = 10 D.

The power of accommodation is (near power) - (far power). With the first example in each of the above, it would be 10 D - 1.5 D = 8.5 D.

Caveats

I’m not entirely sure how cylinder affects this measurement, so you’ll have to refine the technique if you have cylinder.

The cornea and lens actually have more power because the total power has to focus the image on your retina, but they cancel out in the subtraction step, so it’s easier to ignore them.

Videos



Resources